$x-3y+2x+4$
$\frac{x^5+3x^3+6x-2}{x^3+x}$
$\left(\sqrt{y}+5\right)y'=yt^6e^{t^7}$
$75\:+\:\left(-12\right)\:+\:2\:$
$8a^3b^2+6a^3b^2$
$\lim_{x\to-4}\left(x+4\right)$
$\frac{\left(\frac{1}{3}\right)^{6}}{2\cdot3^{6}>3^{6}}$
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