$\int7x\left(\sqrt{6x^2+3}\right)dx$
$y=\ln\left(\frac{6x-5}{x\sqrt{x^{2}+1}}\right)$
$x^4+6x^3+9x^2-4x-12$
$14.6\:-15$
$\frac{dy}{dx}=9y^2sin\left(x\right)$
$\frac{dy}{dt}=\frac{\sqrt{1-y^2}}{t}\:$
$-4x-5<3x+2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!