$\int\frac{x}{\left(x^2+1\right)^{\frac{3}{2}}}dx$
$\left[\left(-2\right)^3\right]^2<\left(-2\right)^5\cdot\left(+1\right)^5$
$\left(6x^3y^3\right)^5$
$14.653+34.56$
$\left(3x+4\right)\left(2x-1\right)$
$x^4.x^4.x$
$\frac{dy}{dt}=\frac{y+3}{1-y}$
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