$-3x\:+\:3y=5$
$\frac{x+5}{x+1}+1=\frac{x-5}{x-2}$
$y'=6\sqrt{y}$
$\sqrt[5]{\left(-4\right)^{15}}$
$10x-8=8x$
$\frac{5}{6}x+8\ge2x-9$
$\frac{dy}{dx}\left(x^3y\right)=0$
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