$-2\:-\:6\:\cdot\left(-1\right)$
$x^2y'=0$
$\frac{x^4}{x^3}$
$17c+6c$
$\int x^{\frac{2}{3}}lnxdx$
$\int\left(\left(x+1\right)^2\right)^{-\frac{2}{3}}dx$
$3-2^2-1\cdot3$
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