∫1∞(1−1+x+x2)dx\int_1^{\infty}\left(\frac{1}{-1+x+x^2}\right)dx∫1∞(−1+x+x21)dx
4x3+3x2−8x4x^3+3x^2-8x4x3+3x2−8x
(bn+2)(bn+3)\left(b^n+2\right)\left(b^n+3\right)(bn+2)(bn+3)
x2−4−4x^2-4-4x2−4−4
2x2−242x^2-242x2−24
∫3x(4x−2)4dx\int3x\left(4x-2\right)^4dx∫3x(4x−2)4dx
10b−3b−4b10b-3b-4b10b−3b−4b
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