$\int\frac{\left(6x-3\right)}{x^2-9x+8}dx$
$\sqrt{x^2}-1$
$-2y+9-6y-3$
$\left(-4\right)^5\:x\:\left(-4\right)^7$
$5x^2+40x=0$
$\left(20.4\right)\cdot\left(-30.6\right)$
$12-4n$
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