$\int_{\sqrt{2}}^a\frac{1}{x\sqrt{x^2-1}}dx$
$3x^2+2x;\:x=1$
$x=x+5$
$\left(6^{-3}\right)^{-1}$
$18-\left(-7\right)$
$\frac{10y^{-3}\:z^{-2}\:}{2y^{-3}\:z^2\:}$
$\frac{1}{4}l\cdot\:\frac{1}{2}l$
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