$8-4y=20$
$\int\sin\left(3x\right).\tan\left(3x\right)dx$
$\lim_{x\to4}\left(\frac{\left|x^2-16\right|}{4-x}\right)$
$\frac{dy}{dx}-4y=20$
$\lim_{h\to-5}\frac{5h+4}{h+8}$
$\int e^u\cdot u$
$\int\frac{5x+1}{5x^{2}}dx$
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