$20-\left(-11\right)$
$4a^5+4a^3+4a$
$\left(2xy\right)dy\:=\:\left(4x^2+3y^2\right)dx$
$-\left(x+3\right)\left(x+7\right)$
$-4n^2m^5-4n^2m^5$
$100-140+49y^2$
$\frac{dy}{dx}+\frac{3y}{x}=3x^2$
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