$\log\left(8\right)+\log\left(8\right)=3\log\left(x\right)$
$\left(x^3\right)^{\frac{3}{2}}$
$4a^2b+3\left(-2a^2b\right)+8a^2b$
$y=\frac{\sqrt{3x^2}}{2}$
$y=ln\sqrt{x}^2-1$
$-1+2+-1+-3$
$4x^2\:+3x^2-4x$
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