$^{-3^2}$
$\int x^8\ln\left(2x\right)dx$
$\int tg^2\:axdx$
$2.8-.3$
$\frac{ex+f}{\left(x-1\right)\left(x+3\right)}=\frac{a}{x-1}+\frac{b}{x+3}$
$4y^3-3.84x$
$\left(m+\frac{1}{m}\right)^2=3$
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