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Exercise

$x^2\:-\frac{2}{5}x\:+\frac{1}{2}5$

Step-by-step Solution

1

Wenden Sie die Formel an: $a+\frac{b}{c}$$=\frac{b+ac}{c}$, wobei $a=x^2$, $b=-\frac{2}{5}\cdot +1$, $c=25$, $a+b/c=x^2+\frac{-\frac{2}{5}\cdot +1}{25}$ und $b/c=\frac{-\frac{2}{5}\cdot +1}{25}$

$\frac{-\frac{2}{5}\cdot +1+25x^2}{25}$

Final answer to the exercise

$\frac{-\frac{2}{5}\cdot +1+25x^2}{25}$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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