$\left(\left(\left(4\right)^2\right)^1\right)^6$
$\frac{-4x+39}{x-8}\ge-5$
$\frac{dy}{dx}\left(\frac{\left(4x-5\right)^3}{x^2-1}\right)$
$\int\sqrt[3]{3f}dx$
$\frac{3x-6>2}{x}$
$\frac{2^3-8}{2-1}$
$x^2-2x+x$
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