$2x^4-4x$
$-17+\left(-7\right)-\left(5\right)+\left(-10\right)-\left(-2\right)+4-57$
$\left(10a-22\right)^2$
$\frac{2x^4-3x^2-5x-6}{x+3}$
$\frac{3x+2}{5}>3x+4$
$\frac{5x^{-2}}{6}$
$\frac{7}{6}+\frac{5}{6}$
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