x2−10x=1x^2-10x=1x2−10x=1
−35x=9-\frac{3}{5}x=9−53x=9
(4x3−16)3( 4 x ^ { 3 } - \frac { 1 } { 6 } ) ^ { 3 }(4x3−61)3
−e0+c-e^0+c−e0+c
3−(−4)+5−{2−(4−(−7)+10)}3-\left(-4\right)+5-\left\{2-\left(4-\left(-7\right)+10\right)\right\}3−(−4)+5−{2−(4−(−7)+10)}
(x2−3a)2\left(x^2-3a\right)^2(x2−3a)2
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