$\left(m-7\right)\left(m+3\right)$
$\lim_{x\to\infty}\left(\frac{x^3-4x^2+8}{2x-6x^2}\right)$
$\sqrt[3]{5x+10}-5=0$
$\lim_{x\to\infty}x^2-x$
$3\cdot22\cdot5$
$x^2-7x+44>0$
$\left(2x^2-2x+3\right)^2$
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