$\:\frac{8x^3+1}{2x-1}\:$
$9x^2-12x+1=0$
$4x^2-12x-40=0$
$\int\left(\frac{x^2-3x+1}{x^2-2x-3}\right)dx$
$\left(-6\right)^6\cdot\left(-4\right)^6$
$\frac{dy}{dx}=\frac{x+2y}{-\left(2x-3y\right)}$
$7\:+\:7\:x\:1\:-\:2\:+\:5$
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