$\int\:4\:ln\:9x\:dx$
$3x-5\left(-2+4x\right)$
$\left(1-x\right)x$
$1.5-\left(-9.5\right)$
$\int_4^9\left(\frac{1}{\left(x-4\right)^2}\right)dx$
$\frac{\left(m^3+n^3\:\:\right)}{\left(m^2-mn+n^2\right)\left(m+n\right)}$
$\frac{3x+2}{5}>3x+4$
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