$2\sin^21=0$
$\lim_{x\to\infty}\left(\frac{1}{3\left(ln\left(x\right)\right)^2+2}\right)$
$16a+5+4$
$\left(a+b\right)^2+c^2,\:a=-2,\:b=1\:c=-2$
$-8.05=n-7.6$
$-8+j=11$
$\frac{1-2\sin^2x}{\cos x+\sin x}+\sin x=\cos x$
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