$\frac{36x^5}{9x}$
$\frac{\left(x^6-3x^2+5x-8\right)}{x^2-3x+1}$
$5x^2-y^3=-7$
$2.5\cdot\left(-12\right)$
$x^2+5x-9$
$\frac{1+\sin\left(4a\right)-\cos\left(4a\right)}{1+\sin\left(4a\right)+\cos\left(4a\right)}$
$4\left(-1\right)^2\:-7$
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