$\lim_{x\to0}\left(\frac{1+e^{-2x}}{1-e^{-2x}}\right)$
$\frac{5x+7}{3}+\frac{7-2x}{7}<5$
$\left(-5\right)-\left(-16\right)$
$-6x^2-7x+155=-8x$
$\frac{9^8}{9^{-6}}$
$9^0$
$\frac{x^2-3x+2}{x-5}$
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