$$\lim_{x\to0}\left(\frac{\ln\left(\sin3x\right)}{\ln\sin x}\right)$$

$$\left(\:+\:12\right)\:-\:\left(\:-\:5\:\right)\:$$

$$\left(w^{-4}\right)^2$$

$$x^2-10x=8$$

$$\left(-5\right)\left(1\right)$$

$$\frac{1}{4}x=2$$

$$3,002\:-\:200$$