$\frac{x^4-x^3+4x+8}{x-3}$
$\left(x^2-3x+1\right)$
$\csc x+\cos x\cot-x=\sin x$
$10\log\left(x\right)=78\log\left(x\right)$
$1.5x-4.2+x-1.9$
$xy+5=0$
$\frac{4x-5}{2}$
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