$\lim_{x\to\infty}\left(\frac{\left(x+1\right)^{\frac{3}{2}}}{\left(x+2\right)^{\frac{3}{2}}}\right)$
$\frac{\tan\left(x\right)}{\sec x-1}$
$\sqrt[3]{-64x^9y^2}$
$8\cdot9+2\cdot5+3$
$\frac{cos\theta\:-cos3\theta\:}{sen\theta\:+sen3\theta\:}=tan\theta\:$
$3x+3x\cdot3y$
$ab^2\cdot ab^2$
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