$\lim_{x\to\infty}\left(\frac{2x^2-5x-3}{x^2}\right)$
$x^2-5x-84=0$
$\left(5x+x^2\right)^2$
$\frac{x^4+x^2+2}{x-2}$
$\left(5x+4\right)\left(x-3\right)$
$3^4.3^7.3^0$
$1-\sin^2x=\frac{1}{\csc^2\left(x\right)}$
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