$x+x+x+\frac{1}{2}x$
$\frac{3}{4}\:=\:\frac{1}{4}\:$
$\left(5\:x\:-6\:x\:-5\:x\:20\right)$
$\left(3x-22\right)^2$
$\frac{2\left(3\right)}{2}\left(3\right)$
$\int x\left(x^2+8\right)^4dx$
$\frac{39z^3-18z^2}{6z^3+5z^2}\cdot\frac{42z+35}{60z-36}$
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