$m^{-2}\left(n^3\right)$
$\left(4x^2-5x+3\right)+6$
$\:x^7-128$
$a^6-9$
$\frac{x^3+8}{x-4}$
$10\sqrt[5]{a^2}bc^3$
$\left(-36\right)-\left(-70\right)-\left(11\right)$
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