$\left(6a+c^4\right)^3$
$x\:+\:5\:\ge15$
$+4-13+2-23+3-1+16-17-2-5$
$x^8-64$
$3m\left(5m^2-3m\right)$
$\lim_{x\to\infty}\left(\frac{-5\ln\left(x^2\right)}{3x^2-8x-3}\right)$
$\frac{2}{\left(x^2-10x+24\right)}$
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