$x^3-27=0$
$4\cdot5+8-\left(5-4\right)$
$3x^7y^3+5x^3y^8-4x^{3\left(n-4\right)}y^3$
$\left(10a-3\right)^2$
$\lim_{x\to+\infty}\left(3x^3+9x^2-x-3\right)$
$\frac{\infty}{-4}$
$-0,25\cdot5$
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