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Exercise

4sec⁡2xcsc⁡2x−2csc⁡2x−2sec⁡2x+14\sec^2x\csc^2x-2\csc^2x-2\sec^2x+1

Step-by-step Solution

1

Factoring by sec⁡(x)2\sec\left(x\right)^2

sec⁡(x)2(4csc⁡(x)2−2)−2csc⁡(x)2+1\sec\left(x\right)^2\left(4\csc\left(x\right)^2-2\right)-2\csc\left(x\right)^2+1

Final answer to the exercise

sec⁡(x)2(4csc⁡(x)2−2)−2csc⁡(x)2+1\sec\left(x\right)^2\left(4\csc\left(x\right)^2-2\right)-2\csc\left(x\right)^2+1

Try other ways to solve this exercise

  • Choose an option
  • Find the derivative
  • Integrate using basic integrals
  • Verify if true (using algebra)
  • Verify if true (using arithmetic)
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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Similar Questions Solved

tan(x)csc(x)tan\left(x\right)csc\left(x\right)

tan⁡(x)csc⁡(x)\tan\left(x\right)\csc\left(x\right)

2+tan⁡2(x)sec⁡2(x)−1\frac{2+\tan^2\left(x\right)}{\sec^2\left(x\right)}-1

2+tan2xsec2x−1\frac{2+tan^2x}{sec^2x}-1

1+tan⁡(x)1+cot⁡(x)\frac{1+\tan\left(x\right)}{1+\cot\left(x\right)}

sin(x)cos(x)+cos(x)sin(x)\frac{sin\left(x\right)}{cos\left(x\right)}+\frac{cos\left(x\right)}{sin\left(x\right)}

tan⁡(x)+cot⁡(x)\tan\left(x\right)+\cot\left(x\right)

Main Topic: Factorization

In mathematics, factorization or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original.

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4sec2xcsc2x−2csc2x−2sec2x+1
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