$\frac{\sin\left(3x\right)}{5x^3-4x}$
$\left(2m^2-1\right)^3$
$\left(4+a^2\right)\left(4-a^2\right)$
$-5m-7m+m$
$5\left(a-1\right)\left(a+3\right)$
$\left(\frac{2^2}{3^4}\right)^0$
$a=ln\left(\frac{b+x}{x}\right)$
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