$\frac{7}{7}\cdot4$
$\frac{4095}{13}$
$\sqrt{36a^8}$
$\left(4a^2-3b^2\right)^2$
$\left(4x-3y\right)\left(76x^3y^2+32x^2y^3\right)$
$d^2+8d+16^2$
$4y^{-2}z^4$
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