$\frac{1}{4}b^3c-\frac{1}{6}b^3c+2b^3c-3b^{3c}$

$x^2+19x+25$

$4x\left(x^2+2\right)^2$

$7\left(13-2x\right)-9\left(x+10\right)$

$\sqrt{1^3+2^3+3^3+4^3+5^3}$

$-\frac{5}{3}\left(3x^3+3x^2-8x-5\right)$

$\left(1+cot^2\left(y\right)\right)\left(cos\left(2y\right)+1\right)=2cot^2\left(y\right)$