$3x-4\le x+8$
$\int x^2.ln\left(x^{-1}\right)dx$
$\left(x+\frac{3}{2}\right)\left(x+\frac{5}{4}\right)$
$\frac{3x^2+x+2}{x+2}$
$\frac{9-x^2}{3+x^2}$
$y^3-3y^2-4y+12$
$3x+6>12$
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