$6x-8>x^2$
$\frac{1-\sin\left(t\right)}{1+\sin\left(t\right)}=\left(\sec\left(t\right)-\tan\left(t\right)\right)^2$
$7\cdot80\cdot40$
$\lim_{x\to\infty}\left(\frac{2x^2}{e^x}\right)$
$2+0+-5$
$\frac{d}{dx}\left(x^4-12xy+y^4=1\right)$
$11+se+1+sec\left(x\right)$
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