$\:\left(4x-7\right)\left(4x+2\right)\:$
$abc+\frac{1}{2}abc+abc+\frac{1}{2}abc$
$\frac{dy}{dx}=\frac{1}{\sqrt[3]{x+2}}$
$4x+10<-2x-8$
$4x+2<6$
$xy'-3y=x^3$
$y=\left(x\:+12\right)^2+162$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!