$\left(-6-2\right)\left(3^2-4\right)$
$\lim_{x\to\infty}\left(\frac{\ln\left(x\right)}{-2e^x}\right)$
$x^3+4^2-3x+8$
$100\:-\:-21$
$\left(\sqrt[3]{2-1}\right)\left(\sqrt[3]{2-1}\right)$
$\int\frac{x^2+3x+1}{x-1}dx$
$a^2b^2-4ab$
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