$\left(\frac{8}{4}\right)^3$
$\cos\left(60\right)+\sin\left(60\right)=\tan\left(60\right)$
$256x^{12}m^4-625y^8$
$36^2-48a+16$
$\left(-6\right)\left(-10\right)\left(-5\right)$
$\left(3x^5+3x\right)^2$
$\left(3x^3+2\right)^2$
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