$\int\frac{\left(2x^2-9x+6\right)}{\left(x^3-x^2-6x\right)}dx$
$\left(x-1\right)\left(x^3-3x^2+3x-1\right)$
$\cos\left(x\right)\left(\sin\left(x\right)-\cos\left(x\right)\right)\sin\left(x\right)^2$
$3x^2-y=-8$
$15x^2-55x$
$5ax-5x-9ay+9y$
$\frac{dx}{dy}=cos\left(x-y\right)$
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