$y=\frac{3}{4}\tan^{-1}\left(x\right)$
$\lim_{x\to0}\left(\frac{\left(x^2-36\right)\left(x-6\right)}{x^2-12x+36}\right)$
$\int u^5e^{\left(1-u^6\right)}\:du$
$\frac{3x^3-2x^2-2x-1}{x+1}$
$\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}$
$10x-25x^4$
$\sqrt{ax^2}$
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