$\frac{14x^2-12+2x}{7x-3}$
$0.34x=0.18x+4$
$x+2>4x-3$
$-7x\left(-4y^2\right)+6y^3\left(5x+1\right)$
$4,42+0,282$
$4\left(8x\right)\left(\frac{3}{8x}\right)$
$6\left(3x\right)\:-\:2y\:+\:3z\:+12\left(4x\right)\:-\:9y$
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