$\frac{7}{2-4x}$
$\int\frac{8}{2x^2-x-3}dx$
$\left(2x^2\right)\left(3xy\right)\left(xy\right)$
$\int\frac{x^2}{\left(\sqrt{4x^2-4x-3}\right)}dx$
$x^{-1}.\:x^{-2}$
$-4r+s-2r-3s$
$\frac{1-\cos\left(a\right)}{1+\cos\left(a\right)}=\tan^2\frac{a}{2}$
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