$3x^2-6x\:+0$
$\left(-8\right)^{3}\cdot\left(-8\right)$
$\sqrt{4}x$
$-5-\left|4-1+3\right|:\left(+2\right)-\left(10-8\right)$
$-2\cos2x=2\sin x$
$-12\left(3\right)^2$
$\frac{2x^2-11x+8}{x+4}$
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