$\int\frac{\left(2x^2+5c+6\right)}{\left(x+2\right)^2\left(x+1\right)}dx$

$6x^3+x^2-12x$

$\frac{1}{x+2}+\frac{1}{x+2}$

$x^3-3x^2-144x-140$

$\left(x^3+x^2\right)^3$

$a\left(x\right)=\frac{8x^{2}\left(4x+3x^{2}-5x^{3}\right)}{4x^{2}}$

$18-\frac{\left(3^2-1\right)}{\left(3+1\right)}$