$\sqrt[3]{a^2-b^{-4}}$
$\lim_{x\to6}\left(\frac{x^2-1}{x^2-5x-6}\right)$
$24=7x+3$
$\left(6x^4-10x^3-12x^2-6x+3\right)+\left(3x^4-2x^3-6x^2+6x-7\right)$
$n-8=-10$
$\frac{-21x^8y^2}{-3y^5y^22}$
$\left(6x^4-8y^5\right)\left(6x^4+y^5\right)$
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