$36+12m^2-m^2$
$x^4\cdot x^8$
$10u\left(2c-d^3\right)+4c-2d^3$
$\int x^2\left(x^3\:+\:1\right)^{\frac{3}{4}}\:dx$
$3a-\:a^3+4a^4\:+\:6a^2$
$\left(\frac{-4}{1}z\right)-\left(\frac{3}{5}z\right)$
$10^1\cdot10^2$
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