$\frac{d}{dx}\left(\sqrt[3]{\frac{\left(5x+1\right)\left(x+4\right)^2}{\left(x^4+5\right)\left(x+8\right)}}\right)$
$3\sec\left(x\right)-\frac{1}{\cos\left(x\right)^2}=2$
$7x+4y-11=0$
$\frac{3}{5}x+\frac{24}{25}y-1z=0$
$-2a^2-4a+6$
$12y^8-2y^8+8y^8$
$5y-3,22y+2,8$
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