$2x+x^2+3\:;\:x=1$
$a^2+2x+1=0$
$\int1+\frac{1}{\log\left(x\right)}dx$
$\sqrt{-16}\:+\:\sqrt{-64}\:+\:\sqrt{-36}\:$
$\frac{dy}{dx}=\left(3t^2+1\right)\:y\left(1\right)=s$
$\frac{2x^2-15}{x+4}$
$1\cdotx^{2}+x$
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