$16x^2-4x+25$
$1+cot^2b=csc^2b$
$\log_{\frac{1}{2}}\left(\left(2x\right)^{-1}\left(x+2\right)^{-1}\right)=\log_{\frac{1}{2}}\left(\frac{1}{16}\right)$
$\left(3x^2-\:2y\right)^2$
$7-4x>7+7x$
$4.8-\frac{1}{4.8}$
$\left(-2x+3y-4z\right)^{2}$
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